completed multiples of 3 and 5

multiplesOf3and5/multiple.c

@@ -0,0 +1,15 @@
+#include <stdio.h>
+
+int main(void){
+	
+	int upperbound = 1000;
+
+	int total = 0;
+
+	int i;
+	for(i = 0; i < upperbound; i++)
+		if(i % 3 == 0 || i % 5 == 0)
+			total += i;
+	
+	printf("the total of all multiples of 3 and 5 up to %i is %i\n", upperbound, total);
+}